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30b^2+37b-9=-19
We move all terms to the left:
30b^2+37b-9-(-19)=0
We add all the numbers together, and all the variables
30b^2+37b+10=0
a = 30; b = 37; c = +10;
Δ = b2-4ac
Δ = 372-4·30·10
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-13}{2*30}=\frac{-50}{60} =-5/6 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+13}{2*30}=\frac{-24}{60} =-2/5 $
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